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| Iron Ore |
The iron ore when is converted to sponge iron the appearance of iron is completely changed with more or less its coposition. Therefore it is important to know the conception of sponge iron before going details to the production.
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| Sponge Iron |
The Oxygen concentration in Hematite iron ore is as Follows
Fe2O3 ----> 2 X Fe + 3O2 ---> 2 X 55.85 + 3 X 16
In the hematite ore 111.70 parts of iron combine with 48 part of oxygen.
when Hematite iron ore is of 65% Fe oxygen will be calculated as follows.
111.70 Parts of Fe contains 48 Parts of O2
1 Parts of Fe contains 48/111.70 Parts of O2
65 Parts of Fe contains (48*65)/111.70 = 27.93 Parts of O2
The Coposition of heatite iron ore is as follows.
- Fe
- O2, SiO2, Al2O3, CaO, MgO, Pb, Cu, Zn, V, S, P = Gangue
- LOI
During Reduction reaction Only O2 and LOI are reoved and all other elements remains intact.
So after reduction reaction the hematite ore is called DRI/Sponge iron and the weght of the product becomes lighter due to removal of O2 and LOI.
the Chemical composition of 65% hematite iron ore is supposed to be as follows.
Fe = 65%
O2 = 27.93%
SiO2+Al2O3 = 4.52%
CaO & MgO etc = 1.00%
LOI = 1.55%
Total = 100.00%
After 100% reduction of oxygen the sponge iron contains
Fe = 65%
O2 = 27.93%
SiO2+Al2O3 = 4.52%
CaO & MgO etc = 1.00%
LOI = 1.55%
Total = 70.52% 29.48 = 100%
So like scrape the Fe(Iron) contains in sponge iron goes high depending on Fe% in Ore.
Read More Post
CONCEPTION OF SPONGE IRON
Process Description and flow diagram of Coal Based DRI Plant
Theories of Re-Oxidation of DRI
Proximate and Ultimate analysis of coal
Some of Required Properties Of Iron Ore for Sponge Iron Operation.
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